Proof: Similar Triangles 3     
line PQ line RS
QT = 8
RT = 4
ST = 3
PS = 9
1. 
1. 
P S
PS = 6 + 3; PS = 9
PT = 6
PS = PT + ST
RT = 4
QT = 8
line PQ line RS
3 / PT = 4 / 8; 3 / PT = 1 / 2
PTQ ~ STR
PTQ STR
ST / PT = RT / QT
ST = 3



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