Proof: Similar Triangles 3
line PQ
line RS
QT = 8
RT = 4
ST = 3
PS = 9
1.
1.
PT = 6
3 / PT = 4 / 8; 3 / PT = 1 / 2
PTQ ~
STR
line PQ
line RS
PTQ
STR
ST / PT = RT / QT
ST = 3
QT = 8
P
S
RT = 4
PS = 6 + 3; PS = 9
PS = PT + ST
ProveIt!
by Michael Ferraro <
mferraro@balstaff.org
>.
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