Proof: Similar Triangles 3     
line PQ line RS
QT = 8
RT = 4
ST = 3
PS = 9
1. 
1. 
P S
QT = 8
PS = PT + ST
line PQ line RS
PS = 6 + 3; PS = 9
ST / PT = RT / QT
PTQ ~ STR
ST = 3
PTQ STR
3 / PT = 4 / 8; 3 / PT = 1 / 2
RT = 4
PT = 6



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